RE: [SQL] datediff function
От | Herouth Maoz |
---|---|
Тема | RE: [SQL] datediff function |
Дата | |
Msg-id | l03130304b3df2a36b34d@[147.233.159.109] обсуждение исходный текст |
Ответ на | RE: [SQL] datediff function ("Pham, Thinh" <tpham@mail.priority.net>) |
Список | pgsql-sql |
At 17:37 +0300 on 17/08/1999, Pham, Thinh wrote: > select datediff(minute, timein, timeout) as totaltime from schedule > > It would give me the number 60, that's it. I don't want any qualifier behind > the number since it blew up the stupid microsoft ADO driver like you > wouldn't believe. If you don't want to write 'now'::datetime you can always write datetime('now'). Same goes for '1 week'::timespan and timespan( '1 week' ). I don't think this will blow up your Microsoft product, but then again, anything can blow up a Microsoft product, being a Microsoft Product included... To make things clear, here is what Postgres can and cannot do: It can give you the interval between two dates. The returned value is an integer representing the number of days between them. It can give you the interval between two datetimes. The returned value is a timespan, expressing days, hours, minutes, etc. as needed. Another method to get the same thing is using age( datetime1, datetime2 ). This returns a timespan, but expressed in years, months, days, hours and minutes. There is a subtle difference here, because a year is not always 365 days, and a month is 28-31 days, depending... You can also truncate datetimes, dates, and other date related types, to the part of your choice. Truncate it to the minute, and it drops the seconds, and gives it back to you with 00 in the seconds. Truncate it to days and it gives it back to you at 00:00:00. This is done with date_trunc(). Another useful operation which can be done is taking one part of the datetime (or related type). For example, the minutes, the seconds, the day, the day of week, or the seconds since the epoch. Now, I'm not sure these functions do exactly what you wanted. It depends on what you expect from datediff(minute, timein, itmeout) when they are not on the same day. For 13-oct-1999 14:00:00 and 14-oct-1999 14:00:05, do you expect 5 or 24*60 + 5? If only 5, then you can do it with SELECT date_part( 'minute', datetime1 - datetime2 ) If not, you will have to do the 24*60 calculation in full. Herouth -- Herouth Maoz, Internet developer. Open University of Israel - Telem project http://telem.openu.ac.il/~herutma
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